How do you convert $(6, 0)$ $(6, 0)$ to polar form?

Question

3371 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-15T03:42:02

Polar coordinates $(r, θ) = (6, 0)$ $(r, theta) = (6, 0)$

To convert from Cartesian Coordinates $(x, y)$ $(x,y)$ to Polar Coordinates $(r, θ)$ $(r,theta)$ :

$r = \sqrt{x^{2} + y^{2}}$ $r = sqrt( x^2 + y^2 )$

$θ = tan^-1 ( y / x )$

Given $x = 6, y = 0$

$r = sqrt(6^2) = 6$

$tan theta = 0 / 6 = 0 " or " theta = 0$

How do you convert (6, 0)(6,0) (6, 0) to polar form?