Question

How do you convert `(6, 0)` to polar form?

Answer 1

Polar coordinates `(r, theta) = (6, 0)`

Explanation:

To convert from Cartesian Coordinates `(x,y)` to Polar Coordinates `(r,theta)`:

`r = sqrt( x^2 + y^2 )`

`θ = tan^-1 ( y / x )`

Given `x = 6, y = 0`

`r = sqrt(6^2) = 6`

`tan theta = 0 / 6 = 0 " or " theta = 0`