Question

How do you convert `(6, 6)` into polar form?

Answer 1

Make use of a few formulas to get `(6,6)->(6sqrt(2),pi/4)`.

Explanation:

The desired conversion from `(x,y)->(r,theta)` can be accomplished with the use of the following formulas:
`r=sqrt(x^2+y^2)`
`theta=tan^(-1) (y/x)`

Using these formulas, we obtain:
`r=sqrt((6)^2+(6)^2)=sqrt(72)=6sqrt(2)`
`theta=tan^(-1)(6/6)=tan^(-1)1=pi/4`

Thus `(6,6)` in rectangular coordinates corresponds to `(6sqrt(2),pi/4)` in polar coordinates.