How do you convert  r=2sin(theta) into cartesian form?

May 31, 2016

${x}^{2} + {y}^{2} - 2 y = 0$

Explanation:

$\left(x , y\right) = \left(r \cos \theta , r \sin \theta\right) . r$2=x^2+y^2#.

So, ${r}^{2} = 2 r \sin \theta$. In cartesian form, this is

${x}^{2} + {y}^{2} - 2 y = 0$

This can be stardized to the form

${\left(x - 0\right)}^{2} + {\left(y - 1\right)}^{2} = 1$ representing the circle with

center C(0, 1) and radius 1 unit.