How do you convert #r secθ = 3# to rectangular form?

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Answer 1 · 2016-10-19T10:17:43

#x^2+y^2-2x=0#

The relation between polar coordinates #(r,theta)# and rectangular Cartesian coordinates #(x,y)# are given by

#x=rcostheta# and #y=rsintheta# or #r^2=x^2+y^2#

Hence #rsectheta=3# can be written as

#r/costheta=3#

or #r^2/(rcostheta)=3#

or #(x^2+y^2)/x=2#

or #x^2+y^2=2x#

or #x^2+y^2-2x=0#