How do you convert #r sec theta = 3# into cartesian form?

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Answer 1 · 2016-09-30T11:08:35

#x^2+y^2=3x#

The relation between polar coordinates #(r,theta)# and Cartesian coordinates #(x,y)# is given by

#x=rcostheta#, #y=rsintheta# and #r^2=x^2+y^2#

Hence #rsectheta=3#

#hArrrxx1/costheta=3#

or #r=3costheta#

or #r^2=3rcostheta#

or #x^2+y^2=3x#
graph{x^2+y^2=3x [-3.867, 5.322, -2.057, 2.538]}