How do you convert $(-sqrt2, 3pi/4)$ to rectangular form?

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Answer 1 · 2016-03-10T12:41:22

$(-sqrt2,(3pi)/4)$ in rectangular coordinates is $(1,-1)$

$(r,theta)$ in polar coordinates is $(rcostheta,rsintheta)$ in rectangular coordinates.

Hence, $(-sqrt2,(3pi)/4)$ in rectangular coordinates is

$(-sqrt2xxcos((3pi)/4),-sqrt2xxsin((3pi)/4))$ or

$((-sqrt2)xx(-sqrt2/2),(-sqrt2)xxsqrt2/2)$ or

$((2/2),-(2/2))$ or

$(1,-1)$

How do you convert (-sqrt2, 3pi/4) (-sqrt2, 3pi/4) to rectangular form?