# How do you convert cartesian (-sqrt7, 0) to polar form?

##### 1 Answer
Apr 27, 2016

Cartesian form $\left(x , y\right) = \left(- \sqrt{7} , 0\right) = \left(r \cos \theta , r \sin \theta\right)$ transforms to the polar form $\left(r , \theta\right) = \left(\sqrt{7} , \pi\right)$.

#### Explanation:

$x = - \sqrt{7} \mathmr{and} y = 0$.

$r = \sqrt{{x}^{2} + {y}^{2}} = \sqrt{7.} \cos \theta = \frac{x}{r} = - 1 \mathmr{and} \sin \theta = \frac{y}{r} = 0$
So, $\theta = \pi$..