# How do you convert x^2 + y^2 = 36 to polar form?

Jun 23, 2016

$r = 6$

#### Explanation:

From the pass equations

 {(x = r cos(theta)), (y = r sin(theta)) :}

${\left(r \cos \left(\theta\right)\right)}^{2} + {\left(r \sin \left(\theta\right)\right)}^{2} = {6}^{2} \to {r}^{2} = {6}^{2} \to r = 6$