# How do you convert z= 55 to polar form?

Sep 11, 2016

$z = 55 \left(\cos \left(0\right) + i \sin \left(0\right)\right)$

#### Explanation:

The polar form of $z$ looks like

$z = r \left(\cos \theta + i \sin \theta\right)$

where $r$ and $\theta$ are real numbers to be found

From Pythagorean's Theorem,
$r = \sqrt{{55}^{2} + {0}^{2}} = 55$

From trigonometry,
$\theta = {\tan}^{- 1} \left(\frac{0}{55}\right) = 0$