# How do you determine the electron configuration of F?

$F = 1 {s}^{2} 2 {s}^{2} 2 {p}^{5}$
Fluorine is in the $2 n d$ energy level, $p$ block, $5 t h$ column, this means that the electron configuration will end $2 {p}^{5}$
$F = 1 {s}^{2} 2 {s}^{2} 2 {p}^{5}$