Question

How do you determine the number of possible solutions using the rule of law of sines given Angle A=31.9 degrees, a=30.6, b=37.9?

Answer 1

Solve oblique triangle, knowing A = 31.9; a = 30.6 and b = 37.9

Explanation:

Find angles B and C.

`sin B = (b.sin A)/a = (37.9(0.53))/30.6 = 20.09/30.6 = 0.65` ->

-> B = 41.03 deg

Angle C = 180 - A - B = 180 - 31.9 - 41.03 = 107.07 deg

`c = a(sin C/sin A)` = 30.6(0.96/0.53) = 30.6( 1.81) = 55.43