How do you determine the slope and y-intercept of the graph of 12+3y= -2x?

1 Answer
Oct 5, 2016

Answer:

slope #=-2/3#
y-intercept = -4

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is

#color(red)(bar(ul(|color(white)(a/a)color(black)(y=mx+b)color(white)(a/a)|)))#
where m represents the slope and b, the y-intercept.

The advantage to having the line in this form is that m and b may be extracted 'easily ' from it.

#12+3y=-2x" can be written in this form"#

subtract 12 from both sides.

#cancel(12)cancel(-12)+3y=-2x-12#

#rArr3y=-2x-12#

divide both sides by 3.

#(cancel(3) y)/cancel(3)=-2/3 x-12/3#

#rArry=-2/3x-4larr" now in form y=mx+b"#

#rArr"slope" =-2/3" and y-intercept" =-4#
graph{-2/3x-4 [-10, 10, -5, 5]}