# How do you determine whether (0,1) is a solution to y > 5/3x - 4?

You fill in the values of $x \mathmr{and} y$ and see if this is correct
$x = 0 \mathmr{and} y = 1$
$1 > \frac{5}{3} \cdot 0 - 4 \to 1 > 0 - 4 \to 1 > - 4$
This is correct, so $\left(0 , 1\right)$ is a solution.