How do you determine whether the pair (1,0) is a solution to y<x^3-4x^2+2?

Dec 6, 2016

As the statement is not true then (1,0) is not a solution

Explanation:

Given:$\text{ } \left(x , y\right) \to \left(1 , 0\right)$

Substitute the values and if the resulting statement is true then (1,0) is a solution.

Consider the right hand side (RHS)

${x}^{3} - 4 {x}^{2} + 2 \text{ "->" } {\left(1\right)}^{3} - 4 {\left(1\right)}^{2} + 2 = - 1$

The ordered pair (1,0) needs to satisfy

LHS < RHS" "->" "0<-1 color(red)(" "larr" False")

As the statement is false then (1,0) is not a solution