How do you differentiate #1 / ln(x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Calculators 1 Answer Andrea S. Jan 9, 2017 #d/(dx) (1/(lnx)) = -1/(xln(x)^2)# Explanation: Using the chain rule: if #y=ln(x)# and #u=1/y# then: #(du)/(dx) = (du)/(dy)*(dy)/(dx)# So: #d/(dx) (1/(lnx)) = -1/(ln(x)^2)*1/x= -1/(xln(x)^2)# Answer link Related questions How do you use a calculator to find the derivative of #f(x)=e^(x^2)# ? How do you use a calculator to find the derivative of #f(x)=e^(1-3x)# ? How do you use a calculator to find the derivative of #f(x)=e^sqrt(x)# ? What is the derivative of #e^(-x)#? What is the derivative of #ln(2x)#? How do you differentiate #(lnx)^(x)#? How do you differentiate #x^lnx#? How do you differentiate #f(x) = e^xlnx#? How do you differentiate #e^(lnx) #? How do you differentiate #y = lnx^2#? See all questions in Differentiating Exponential Functions with Calculators Impact of this question 8830 views around the world You can reuse this answer Creative Commons License