# How do you differentiate f(x)=e^tan(1-x^2)  using the chain rule?

$\frac{d}{\mathrm{dx}} {e}^{\tan \left(1 - {x}^{2}\right)} = - 2 x {\sec}^{2} \left(1 - {x}^{2}\right) {e}^{\tan \left(1 - {x}^{2}\right)}$
$\frac{d}{\mathrm{dx}} {e}^{\tan \left(1 - {x}^{2}\right)} = {e}^{\tan \left(1 - {x}^{2}\right)} \cdot {\sec}^{2} \left(1 - {x}^{2}\right) \cdot \left(- 2 x\right)$