# How do you differentiate the following parametric equation:  x(t)=lnt-t, y(t)=(t-3)^2 ?

$\frac{\mathrm{dx}}{\mathrm{dt}} = \frac{1}{t} - 1$
$\frac{\mathrm{dy}}{\mathrm{dt}} = 2 \left(t - 3\right)$