# How do you differentiate the following parametric equation:  x(t)=t^2+cos2t, y(t)=t-sint ?

$\setminus \frac{\mathrm{dy}}{\mathrm{dx}} = \setminus \frac{1 - \cos t}{2 \left(t - \sin 2 t\right)}$
$\setminus \frac{\mathrm{dx}}{\mathrm{dt}} = 2 t - 2 \sin 2 t$
$\setminus \frac{\mathrm{dy}}{\mathrm{dt}} = 1 - \cos t$
$\setminus \frac{\mathrm{dy}}{\mathrm{dx}} = \setminus \frac{\setminus \frac{\mathrm{dy}}{\mathrm{dt}}}{\setminus \frac{\mathrm{dx}}{\mathrm{dt}}} = \setminus \frac{1 - \cos t}{2 \left(t - \sin 2 t\right)}$