How do you differentiate the following parametric equation: $x(t)=-te^t-2t, y(t)= 3t^3-4t$ ?

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Answer 1 · 2017-01-14T07:10:51

The answer is $=-((e^t+te^t+2))/((9t^2-4))$

We need

$(uv)'=u'v-uv'$

$(e^x)'=e^x$

$(x^n)'=nx^(n-1)$

$x(t)=-te^t-2t$

$y(t)=3t^3-4t$

$dx/dt=-(e^t+te^t+2)$

$dy/dt=9t^2-4$

$dy/dx=(dy/dt)/(dx/dt)=-((e^t+te^t+2))/((9t^2-4))$

How do you differentiate the following parametric equation: x(t)=-te^t-2t, y(t)= 3t^3-4t x(t)=-te^t-2t, y(t)= 3t^3-4t ?