Question

How do you divide `(2x^3-x^2+5)÷(x-2)`?

Answer 1

Quotient = `2*x^2+3*x+6`
Remainder = `17`

Explanation:

Without omitting any degrees of the polynomial, the dividend is `2*x^3 - x^2 + 0*x + 5` and the divisor is `x - 2`
Now using the long division method step by step
Q = quotient
R = remainder
Q0 = 0
R0 = `2*x^3 - x^2 + 0*x + 5`
Q1 = `2*x^2`
R1 = `+3x^2+0*x+5`
Q2 = `2*x^2+3x`
R2 = `+6*x+5`
Q3 = `2*x^2+3*x+6`
R3 = `17`