How do you divide $\frac{3 x^{2} + 9 x + 36}{x - 3}$ $(3x^2+9x+36) / (x-3)$ ?

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How do you divide $\frac{3 x^{2} + 9 x + 36}{x - 3}$ $(3x^2+9x+36) / (x-3)$ ?

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Answer 1 · 2018-06-13T07:06:13

$\frac{3 (x^{2} + 3 x + 12)}{x - 3}$ $(3(x^2+3x+12))/(x-3)$

Explanation:

$\frac{3 x^{2} + 9 x + 36}{x - 3}$ $(3x^2+9x+36)/(x-3)$
Factorise $3 x^{2} + 9 x + 36$ $3x^2+9x+36$
$\frac{3 (x^{2} + 3 x + 12)}{x - 3}$ $(3(x^2+3x+12))/(x-3)$
$x^{2} + 3 x + 12$ $x^2+3x+12$ cannot be factorised with rational numbers

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How do you divide $\frac{3 x^{2} + 9 x + 36}{x - 3}$ $(3x^2+9x+36) / (x-3)$ ?

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Explanation:

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How do you divide 3x2+9x+36x−3(3x^2+9x+36) / (x-3) ?

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How do you divide $\frac{3 x^{2} + 9 x + 36}{x - 3}$ $(3x^2+9x+36) / (x-3)$ ?