How do you divide #( -3x^3+ x^2+7x-30 )/(x + 1 )#?

1 Answer
Apr 29, 2016

Answer:

Divide by synthetic division.

Explanation:

#x + 1 = 0#

#x = -1#

I apologize for the following formatting (this is the best I can do!!!):

-1 __| -3, 1, 7, -30

Bringing the -3 down and multiplying with the -1, to give 3, and then adding the 3 to 1 to get 4, and then sending the 4 into multiplication with the -1, continuing the process you end with:

#-3x^2 + 4x + 3#, with a remainder of #-33#

Thus, #(x + 1)(-3x^2 + 4x + 3) - 33 = -3x^3 + x^2 + 7x - 30#

Hopefully this helps!