How do you divide $\frac{- 3 x^{3} + x^{2} - x - 72}{x - 2}$ $( -3x^3+ x^2-x-72 )/(x - 2 )$ ?

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How do you divide $\frac{- 3 x^{3} + x^{2} - x - 72}{x - 2}$ $( -3x^3+ x^2-x-72 )/(x - 2 )$ ?

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Answer 1 · 2016-02-27T13:08:05

$\frac{- 3 x^{3} + x^{2} - x - 72}{x - 2}$ $(-3x^3+x^2-x-72)/(x-2)$
$= \frac{- 3 x^{2} (x - 2) - 6 x^{2} + x^{2} - x - 72}{x - 2}$ $=(-3x^2(x-2)-6x^2+x^2-x-72)/(x-2)$
$= \frac{- 3 x^{2} (x - 2) - 5 x (x - 2) - 10 x - x - 72}{x - 2}$ $=(-3x^2(x-2)-5x(x-2)-10x-x-72)/(x-2)$
$= \frac{- 3 x^{2} (x - 2) - 5 x (x - 2) - 11 (x - 2) - 22 - 72}{x - 2}$ $=(-3x^2(x-2)-5x(x-2)-11(x-2)-22-72)/(x-2)$
$= - 3 x^{2} - 5 x - 11 - \frac{94}{x - 2}$ $=-3x^2-5x-11-94/(x-2)$

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How do you divide $\frac{- 3 x^{3} + x^{2} - x - 72}{x - 2}$ $( -3x^3+ x^2-x-72 )/(x - 2 )$ ?

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How do you divide −3x3+x2−x−72x−2( -3x^3+ x^2-x-72 )/(x - 2 )?

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How do you divide $\frac{- 3 x^{3} + x^{2} - x - 72}{x - 2}$ $( -3x^3+ x^2-x-72 )/(x - 2 )$ ?