How do you divide #( -3x^3+ x^2-x-72 )/(x - 2 )#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer P dilip_k Feb 27, 2016 #(-3x^3+x^2-x-72)/(x-2)# #=(-3x^2(x-2)-6x^2+x^2-x-72)/(x-2)# #=(-3x^2(x-2)-5x(x-2)-10x-x-72)/(x-2)# #=(-3x^2(x-2)-5x(x-2)-11(x-2)-22-72)/(x-2)# #=-3x^2-5x-11-94/(x-2)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1308 views around the world You can reuse this answer Creative Commons License