How do you divide #(6x^3-16x^2+17x-6) / (3x-2) # using polynomial long division? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Cem Sentin Dec 10, 2017 Quotient: #2x^2-4x+3# and remainder: #0# Explanation: #6x^3-16x^2+17x-6# =#6x^3-4x^2-12x^2+8x+9x-6# =#2x^2*(3x-2)-4x*(3x-2)+3*(3x-2)# =#(2x^2-4x+3)*(3x-2)# Quotient: #2x^2-4x+3# and remainder: #0# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1397 views around the world You can reuse this answer Creative Commons License