How do you divide (x^4 + 2x^3 +3x -1) /(x^2+2)x4+2x3+3x1x2+2?

1 Answer
Apr 29, 2018

Using the distribution method, you can expand the expression.

Explanation:

(x^4+2x^3+3x-1)/(x^2+2)x4+2x3+3x1x2+2

distribute the (x^4+2x^3+3x-1)(x4+2x3+3x1) to x^2x2 and 22 and now we get:

(x^4+2x^3+3x-1)/x^2 + (x^4+2x^3+3x-1)/2x4+2x3+3x1x2+x4+2x3+3x12

we can further distribute x^2x2 and 22 to (x^4+2x^3+3x-1)(x4+2x3+3x1):

(x^4/x^2(x4x2++(2x^3)/x^22x3x2++(3x)/x^23xx2-1/x^2)1x2)++((x^4)/2(x42++(2x^3)/22x32++(3x)/23x2-1/2)12)

This is the simplified version:
x^2+2x+3/x-1/x^2+x^4/2+x^3+1.5x-1/2x2+2x+3x1x2+x42+x3+1.5x12

Sorry but I'm not sure of what you are trying to find so I can only give this answer.