# How do you divide (x^4 + 2x^3 +3x -1) /(x^2+2)?

Apr 29, 2018

Using the distribution method, you can expand the expression.

#### Explanation:

$\frac{{x}^{4} + 2 {x}^{3} + 3 x - 1}{{x}^{2} + 2}$

distribute the $\left({x}^{4} + 2 {x}^{3} + 3 x - 1\right)$ to ${x}^{2}$ and $2$ and now we get:

$\frac{{x}^{4} + 2 {x}^{3} + 3 x - 1}{x} ^ 2 + \frac{{x}^{4} + 2 {x}^{3} + 3 x - 1}{2}$

we can further distribute ${x}^{2}$ and $2$ to $\left({x}^{4} + 2 {x}^{3} + 3 x - 1\right)$:

(x^4/x^2$+$$\frac{2 {x}^{3}}{x} ^ 2$$+$$\frac{3 x}{x} ^ 2$$-$1/x^2)$+$((x^4)/2$+$$\frac{2 {x}^{3}}{2}$$+$$\frac{3 x}{2}$$-$1/2)

This is the simplified version:
${x}^{2} + 2 x + \frac{3}{x} - \frac{1}{x} ^ 2 + {x}^{4} / 2 + {x}^{3} + 1.5 x - \frac{1}{2}$

Sorry but I'm not sure of what you are trying to find so I can only give this answer.