How do you evaluate #5/6-2/3#?

3 Answers
Mar 16, 2018

Answer:

#1/6#

Explanation:

Both fractions must have the same denominators before you can add the numerators:.

#5/6 -(2xx2)/(3xx2)#

#=5/6 -4/6#

#=1/6#

Mar 16, 2018

Answer:

#1/6#

Explanation:

#"before subtracting the fractions we require them to have"#
#"a "color(blue)"common denominator"#

#"this is achieved by multiplying numerator/denominator"#
#"of "2/3" by 2, thus making the denominator 6"#

#rArr5/6-((2xxcolor(red)(2))/(3xxcolor(red)(2)))#

#=5/6-4/6#

#"now subtract the numerators leaving the denominator"#

#=(5-4)/6=1/6#

Mar 16, 2018

Answer:

Make both numbers have a common denominator of 6, then just subtract to get #1/6#

Explanation:

To subtract the numerators (numbers at the top), find a common denominator (number at the bottom), which in this case I'll use 6, since 6 is a common multiple of both 6 and 3

So to convert #2/3# to #n/6#, where #n# just stands for some number you want to find, multiply both top and bottom by 2

#2/3=(2*2)/(3*2)=4/6#

So you replace #2/3# with #4/6# in that expression

#5/6-2/3=5/6-4/6=(5-4)/6=1/6#

To get the answer #1/6#