# How do you evaluate Arctan(1/2)+arctan(1/3)?

$a r c \tan 1$=pi/4, the principal against the principal values. The general value is $n \pi + \frac{\pi}{4} , n = 0 , \pm 1 , \pm 2. \pm 3 , \ldots$
Answer is the inverse ${\tan}^{- 1} 1$. Now, see the answer. again.