# How do you evaluate arctan sqrt3?

Trig mostly asks about 30/60/90 and 45/45/90 and their brethren in other quadrants; learn those and you're halfway home. $\setminus \sqrt{3}$ is the former, and a slope of $\sqrt{3} > 1$ means
$\textrm{A r c} \textrm{\tan} \left(\sqrt{3}\right) = {60}^{\circ}$
$\arctan \sqrt{3} = {60}^{\circ} + {180}^{\circ} k \quad$ integer $k$