# How do you evaluate sec(sec^-1(-2/sqrt3))?

$- \frac{2}{\sqrt{3}}$
uSE $F {F}^{- 1} \left(a\right) = a$
Here, $F i s \sec , F {,}^{_ 1} i s {\sec}^{- 1} \mathmr{and} a = \left(- \frac{2}{\sqrt{3}}\right)$.