Question

How do you evaluate `sec(tan^-1(sqrt3))` without a calculator?

Answer 1

`sec(tan^-1(sqrt3))=sec(60^@)=1/cos(60^@) = 1/(1/2)=2`

Explanation:

`sec(tan^-1(sqrt3))`->From the special triangle `30^@-60^@-90^@` we have `tan 60^@=sqrt3` hence `60^@=tan^-1(sqrt3)`

`sec(60^@)=1/cos(60^@) = 1/(1/2)=2`