# How do you evaluate sin^-1 (-1/2)?

$- \frac{\pi}{6} \mathmr{and} \frac{7 \pi}{6}$
$\sin x = - \frac{1}{2}$ --> arc $x = - \frac{\pi}{6}$ and arc $x = \pi + \frac{\pi}{6} = \frac{7 \pi}{6}$
$A n s w e r s : - \frac{\pi}{6} , \mathmr{and} \frac{7 \pi}{6}$