Question

How do you evaluate `sin^-1(1/2)`?

Answer 1

`pi/6`

Explanation:

We know that
`color(red)(sin^-1(sinx)=x,AAx in[-pi/2,pi/2])`
`sin^-1(1/2)=sin^-1(sin(pi/6))=pi/6, where, pi/6in[-pi/2,pi/2]`
So, `sin^-1(1/2)=pi/6`