# How do you evaluate sin^-1(sin(pi/6))?

Oct 19, 2016

$\frac{\pi}{6}$

#### Explanation:

The following is a pretty good definition for any inverse function:

Let $f \left(x\right)$ be a function that has an inverse and let ${f}^{-} 1 \left(x\right)$ be that inverse, then ${f}^{-} 1 \left(f \left(x\right)\right) = x \mathmr{and} f \left({f}^{-} 1 \left(x\right)\right) = x$

Therefore, the inverse sine "undoes" what the sine does.