# How do you evaluate sin^-1(sin(-pi/6))?

$y = - \frac{\pi}{6}$
Let $y = {\sin}^{-} 1 \sin \left(- \frac{\pi}{6}\right)$
Then $\sin y = \sin \left(- \frac{\pi}{6}\right)$
Therefore $y = - \frac{\pi}{6}$