Question

How do you evaluate `sin ( arccos (15/17))`?

Answer 1

`sin x = +- 8/17.`

Explanation:

Call x the arc whose `cos x = 15/17.`
Find sin x.
`sin^2 x = 1 - cos^2 x = 1 - 225/289 = 64/289.`
`sin x = +- 8/17.`