How do you evaluate #tan^-1(tan((7pi)/6))#?
When the operation is "inverse of a function over the function# on
an operand 'a', the result is 'a'.
So, the answer is
The conventional restriction on
'a' as the principal value
has no relevance for this double operation.
If the question is about
the value will be
In either case the tan value =
Of course, the principal value of
The source for the value