Question

How do you evaluate the definite integral of 0 to 4 for `(5 / 3x +1) dx`?

Answer 1

It is `52/3`

Explanation:

It is

`int_0^4 (5/3x+1)dx=int_0^4 (5/3x^2/2+x)'dx=[5x^2/6+x]_0^4=5/6*4^2+4=52/3`