# How do you factor 100m^8 - 9?

May 6, 2015

This fits the form of the difference of squares.

${a}^{2} - {b}^{2} = \left(a - b\right) \left(a + b\right)$

$100 {m}^{8} - 9 = {\left(10 {m}^{4}\right)}^{2} - {3}^{2}$

$a = 10 m$
$b = 3$

$100 {m}^{8} - 9 = \left(10 {m}^{4} - 3\right) \left(10 {m}^{4} + 3\right)$