How do you factor #10x^2-19xy+6y^2#?
Because the sign are,
We can write the following equations:
Three equations and four unknown values is bad.
Let's start by trying 5 for a and 2 for c:
Two equations and two unknown values is good but does it work?
(5x - 2y)(2x - 3y)
Consider x as a variable and y as a constant. Factor this quadratic trinomial by the new AC Method (Socratic, Google Search)
Proceeding. Find p' and q', then, divide them by a = 10.
Find 2 numbers knowing the sum (b = - 19y) and product (60y^2).
They are: (-4y) and (-15y). (sum: -19y and product: 60y^2)
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