How do you factor #10x^2+35x-4x-14# by grouping?

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Answer 1 · 2018-03-30T19:03:48

#10x^2+35x-4x-14 = (5x-2)(2x+7)#

Note that #10x^2# and #35x# are both divisible by #5x# and #4x# and #14# are both divisible by #2#.

So we find:

#10x^2+35x-4x-14 = (10x^2+35x)-(4x+14)#

#color(white)(10x^2+35x-4x-14) = 5x(2x+7)-2(2x+7)#

#color(white)(10x^2+35x-4x-14) = (5x-2)(2x+7)#

Answer 2 · 2018-03-30T19:06:43

#10x^2+35x−4x−14#

#=>5x(2x+7)−2(2x+7)#

#=>(5x−2)(2x+7)#

#color(white)(dd#

Verification,

#(5x−2)(2x+7)#

#=>5x(2x+7)−2(2x+7)#

#=>10x^2+35x−4x−14#