How do you factor #11x^2+11xy+4x+4y#?

2 Answers
Mar 18, 2018

Answer:

A bit rusty with factoring, but I'm pretty sure...

Explanation:

#11x^2 + 11xy + 4x + 4y#

(Use grouping.)

#11(11x^2 + 11xy) + 4(4x + 4y)#

#(x + y)(11x + 4)#

Mar 18, 2018

Answer:

#(x+y)(11x+4)#

Explanation:

#"factorise in groups"#

#color(red)(11x)(x+y)color(red)(+4)(x+y)#

#"take out "color(blue)"common factor "(x+y)#

#=(x+y)(color(red)(11x+4))#

#rArr11x^2+11xy+4x+4y=(x+y)(11x+4)#