Question

How do you factor `12n^3+15n^2+4n+5`?

Answer 1

`12n^3+15n^2+4n+5`

By inspection the first two terms are `3n^2` times the last two terms

`12n^3+15n^2+4n+5`
`=(3n^2)(4n+5) + (1)(4n+5)`

`=(3n^2+1)(4n+5)`