How do you factor #12x^2 + 36xy + 27y^2?

Question

3602 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-08T04:04:59

$f(x) = 3(4x^2 + 12xy + 9y^2) = 3(2x + 3y)^2$

Answer 2 · 2015-06-08T05:31:58

Answer: $12x^2+36xy+27y^2=3(2x+3y)^2$

Problem: Factor $12x^2+36xy+27y^2$ .

Factor out the GCF $3$ .

$3(4x^2+12xy+9y^2)$

$(4x^2+12xy+9y^2)$ is a perfect square trinomial with the pattern

$(a+b)^2=a^2+2ab+b^2$ .

$a=2x$
$b=3y$

$(4x^2+12xy+9y^2)=(2x+3y)^2$

$12x^2+36xy+27y^2=3(2x+3y)^2$