# How do you factor 12x^2 + 4xy + 9x + 3y?

Jul 11, 2016

$\left(3 x + y\right) \left(4 x + 3\right) .$

#### Explanation:

Given Exp. $= 12 {x}^{2} + 4 x y + 9 x + 3 y$

We notice that $4 x$ is common in first & second term, so, taking that common , we are left with $\left(3 x + y\right)$.

Similarly, from third & fourth term, we can take $3$ common, then there remains $\left(3 x + y\right) .$

This way, in turn, we'll have (3x+y) as a common factor. So, the
Given Exp. $= 4 x \left(3 x + y\right) + 3 \left(3 x + y\right)$
$= \left(3 x + y\right) \left(4 x + 3\right) .$

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