How do you factor $12x^2 + 4xy + 9x + 3y$ ?

Question

1368 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-11T14:36:11

$(3x+y)(4x+3).$

Given Exp. $=12x^2+4xy+9x+3y$

We notice that $4x$ is common in first & second term, so, taking that common , we are left with $(3x+y)$ .

Similarly, from third & fourth term, we can take $3$ common, then there remains $(3x+y).$

This way, in turn, we'll have (3x+y) as a common factor. So, the
Given Exp. $=4x(3x+y)+3(3x+y)$
$=(3x+y)(4x+3).$

Enjoyed it?!

How do you factor 12x^2 + 4xy + 9x + 3y12x^2 + 4xy + 9x + 3y?