How do you factor #16n^2+ 43n -15#?

1 Answer
May 31, 2016

Answer:

#(16n-5)(n+3)#

Explanation:

Any quadratic that can be factored can be expressed in the general form #(ax+b)(cx+d) = acx^2 +(ad+bd)x +bd#

We therefore need to find factors of #16# and #-15# that in the right combination will give #43#

#16 =16*1# and #15 =5*3#

#3*16 = 48#

#48-5*1=43#

#:.16n^2+43n-15 = (16n-5)(n+3)#