How do you factor #16x^2+8x-3#?

1 Answer
Oct 2, 2016

Answer:

#(4x-1)(4x+3)#

Explanation:

If you cannot do this by inspection.
Then use the formula.
The solution to #y=ax^2+bx+c# is #y=(-b+-sqrt(b^2-4ac))/(2a)#

So#y=(-8+-sqrt(64-4.16.-3))/32#

Or #y=(-8+16)/32 #or #(-8-16)/32#
Or #y=8/32# or#-24/32#

Or #y=1/4 or -3/4#

This gives the factorisation.....