How do you factor 16x^2+8x-3?

1 Answer
Oct 2, 2016

(4x-1)(4x+3)

Explanation:

If you cannot do this by inspection.
Then use the formula.
The solution to y=ax^2+bx+c is y=(-b+-sqrt(b^2-4ac))/(2a)

Soy=(-8+-sqrt(64-4.16.-3))/32

Or y=(-8+16)/32 or (-8-16)/32
Or y=8/32 or-24/32

Or y=1/4 or -3/4

This gives the factorisation.....