# How do you factor 16x^2+8x-3?

Oct 2, 2016

$\left(4 x - 1\right) \left(4 x + 3\right)$

#### Explanation:

If you cannot do this by inspection.
Then use the formula.
The solution to $y = a {x}^{2} + b x + c$ is $y = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

So$y = \frac{- 8 \pm \sqrt{64 - 4.16 . - 3}}{32}$

Or $y = \frac{- 8 + 16}{32}$or $\frac{- 8 - 16}{32}$
Or $y = \frac{8}{32}$ or$- \frac{24}{32}$

Or $y = \frac{1}{4} \mathmr{and} - \frac{3}{4}$

This gives the factorisation.....