How do you factor # 18x^2-12x-6 # by grouping?
1 Answer
Feb 1, 2017
Explanation:
#18x^2-12x-6 = 6(3x^2-2x-1)#
#color(white)(18x^2-12x-6) = 6((3x^2-3x)+(x-1))#
#color(white)(18x^2-12x-6) = 6(3x(x-1)+1(x-1))#
#color(white)(18x^2-12x-6) = 6(3x+1)(x-1)#
