How do you factor #2(2r^2-5r-6)#?

1 Answer
Feb 14, 2016

See solution below.


Since this trinomial is of the form #ax^2 + bx + c, a != 1, 0#, we have to find two numbers that multiply to the product of #a xx c# and two numbers that add to b.

There are no 2 numbers that multiply to -12 and that add to -5. As a result, this polynomial is factored completely and cannot be simplified any further.

Hopefully this helps!