# How do you factor #2ax+6xc+ba+3bc#?

##### 1 Answer

Jun 7, 2017

#### Explanation:

Let's try to find a way to group these terms.

Hmm... two of the terms have

#a# and two of the terms have#c# .Let's group the two

#a# terms together, and the two#c# terms together, and then factor out#a# and#c# respectively (by the way, this is NOT the only valid way to factor this; you could actually group the terms with#x# together and the terms with#b# together and do the same thing).

#2ax + 6xc + ba + 3bc#

#2ax + ba + 6xc + 3bc#

#a(2x + b) + c(6x+3b)#

We can also pull a factor of

#a(2x+b)+3c(2x+b)#

Now, we can use the converse of the distributive property to group

#(a+3c)(2x+b)#

*Final Answer*