How do you factor #2b^3+3b^28b12# by grouping?
1 Answer
Feb 9, 2017
Explanation:
 If you try to find a connection between 2, 3, 8 and 12. You will find that 2 is the common factor of 2 and 8; 3 is the common factor or 3 and 12.
2.So try group them like above and you will get:

And here comes the answer:
#(2b+3)(b^24)# 
You can further break
#(b^24)# into#(b+2)(b2)# 
The final result is :
#(2b+3)(b+2)(b2)#